Time Limit: 2000/1000 MS
(Java/Others) Memory Limit: 65536/32768 K
(Java/Others)
Total Submission(s): 58415 Accepted
Submission(s): 13985
解题报告:
用一个二维数组保存每个学生的各科成绩。横坐标表示学生,纵坐标表示每个学科。横向遍历数据得到每个学生的平均分,纵向遍历得到每个学科的平均分。用一个一维数组保存每个学生每个学科的平均分,方便求学生成绩大于平均分的人数。
注意输出格式!
#include<stdio.h> int buf[55][8]; double sub_average[5]; int main() { int n, m; int i, j; int count; double sum = 0; while(scanf("%d%d", &n, &m) == 2) { count = 0; for(i = 0; i < n; i++) for(j = 0; j < m; j++) scanf("%d", &buf[i][j]); for(i = 0; i < n; i++) { sum = 0; for(j = 0; j < m; j++) sum += buf[i][j]; if(i) printf(" "); printf("%.2lf", sum /(double)m); } printf("\n"); for(j = 0; j < m; j++) { sum = 0; for(i = 0; i < n; i++) sum += buf[i][j]; sub_average[j] = sum /(double)n; if(j) printf(" "); printf("%.2lf", sub_average[j]); } printf("\n"); for(i = 0; i < n; i++) { for(j = 0; j < m; j++) if(buf[i][j] < sub_average[j]) break; if(j == m) count++; } printf("%d\n\n", count); } return 0; }
原文:http://www.cnblogs.com/la0bei/p/3652910.html