例1:
|
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87 |
package
Test15;import
java.util.HashMap;import
java.util.HashSet;import
java.util.Iterator;import
java.util.Map;import
java.util.Set;import
java.util.Map.Entry;//Map集合遍历public
class Test { private
Map<String, String> map = new
HashMap<String, String>(); public
static void main(String[] args) { Test t=new
Test(); t.setValue(); t.method3(); } //为map赋值 public
void setValue(){ map.put("name", "张三"); map.put("sex", "男"); } //方法1 public
void method1(){ Set<String> set = new
HashSet<String>(); set = map.keySet(); // 获得map中所有Key for
(String s : set) { System.out.println(map.get(s)); } } //方法2 public
void method2(){ Iterator<String> iterator=map.keySet().iterator(); //返回所有key while(iterator.hasNext()){ String key=iterator.next(); System.out.println(key+": "+map.get(key)); } } //方法3 public
void method3(){ Set<Entry<String,String>> set= map.entrySet(); //返回:key和value的封装 for(Entry entry:set){ System.out.println(entry.getKey()+":"+entry.getValue()); } }} |
原文：http://www.cnblogs.com/gdds/p/3643943.html