hdu4004 The Frog's Games 二分

直接贴代码

#include<cstdio>
#include<iostream>
#include<cstring>
#include<cmath>
#include<algorithm>
#include<vector>
#include<queue>
#include<set>
using namespace std;

int stone[500005],dis[500005];
int l,n,m;

bool judge(int p)
{
    if(p*m<l) return false;
    int cnt=0,i=1;
    while(cnt<=m){
        int temp=p;
        for(;i<=n+1;){
            if(temp>=dis[i]){
                temp-=dis[i];
                i++;
            }
            else {
            break;
            }
        }
        cnt++;
        if(i>n+1) break;
    }
    if(cnt>m) return false;
    else return true;
}
int solve(int l,int r){
    int mid;
    while(l<r){
        mid=(l+r)>>1;
        if(judge(mid)) r=mid;
        else l=mid+1;
    }
    return l;
}
int main()
{
    while(scanf("%d%d%d",&l,&n,&m)!=EOF){
        int i;
        memset(stone,0,sizeof(stone));
        for(i=1;i<=n;i++){
            scanf("%d",&stone[i]);
        }
        stone[0]=0;
        stone[i]=l;
        sort(stone+1,stone+1+n);
        for(i=1;i<=n+1;i++) dis[i]=stone[i]-stone[i-1];
        printf("%d\n",solve(1,l));
    }
}

hdu4004 The Frog's Games 二分,布布扣,bubuko.com

hdu4004 The Frog's Games 二分

原文：http://blog.csdn.net/cnh294141800/article/details/22606091