Time Limit: 3000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 5795 Accepted Submission(s):
2384
/*
* 利用优先队列来将最大的优先权的患者
* 输出
* 不太会用优先队列参考了别人代码
* 还写得不简洁 惭愧
*
*/
#include<stdio.h>
#include<string.h>
#include<algorithm>
#include<queue>
using namespace std;
struct node1
{
int time1;
int pat1;
friend bool operator < (node1 a,node1 b)
{
if(a.pat1!=b.pat1)
return a.pat1<b.pat1;
else
return a.time1>b.time1;
}
};
struct node2
{
int time2;
int pat2;
friend bool operator < (node2 a,node2 b)
{
if(a.pat2!=b.pat2)
return a.pat2<b.pat2;
else
return a.time2>b.time2;
}
};
struct node3
{
int time3;
int pat3;
friend bool operator < (node3 a,node3 b)
{
if(a.pat3!=b.pat3)
return a.pat3<b.pat3;
else
return a.time3>b.time3;
}
};
int main()
{
int n,m,t,k,a;
char s1[10];
char str1[5]={"IN"};
while(scanf("%d",&t)!=EOF)
{
priority_queue<node1>q1;//医生1的看病情况
priority_queue<node2>q2;//医生2
priority_queue<node3>q3;//医生3
node1 x1;//定义结构体名
node2 x2;
node3 x3;
k=1;
while(t--)
{
scanf("%s",s1);
if(s1[0]==‘I‘)
{
scanf("%d%d",&n,&m);
if(n==1)
{
x1.time1=k;
x1.pat1=m;
q1.push(x1);
}
else if(n==2)
{
x2.time2=k;
x2.pat2=m;
q2.push(x2);
}
else if(n==3)
{
x3.time3=k;
x3.pat3=m;
q3.push(x3);
}
k++;
}
else
{
scanf("%d",&a);
if(a==1)
{
if(q1.empty())
printf("EMPTY\n");
else
{
x1=q1.top();
printf("%d\n",x1.time1);
q1.pop();
}
}
else if(a==2)
{
if(q2.empty())
printf("EMPTY\n");
else
{
x2=q2.top();
printf("%d\n",x2.time2);
q2.pop();
}
}
else if(a==3)
{
if(q3.empty())
printf("EMPTY\n");
else
{
x3=q3.top();
printf("%d\n",x3.time3);
q3.pop();
}
}
}
}
}
return 0;
}
原文:http://www.cnblogs.com/tonghao/p/4681166.html