#27 Remove Element

题目链接：https://leetcode.com/problems/remove-element/

Given an array and a value, remove all instances of that value in place and return the new length.

The order of elements can be changed. It doesn‘t matter what you leave beyond the new length.

//遍历元素，如果需要删除，用数组最后一个元素填充当前元素；下一个循环依然考察当前元素
int removeElement(int* nums, int numsSize, int val) {
    for(int i = 0; i < numsSize; ++i)
        if(val == nums[i])
            nums[i--] = nums[--numsSize]; 
    return numsSize;
}

#27 Remove Element

原文：http://blog.csdn.net/ice_camel/article/details/46956209