首页 > 其他 > 详细

【LeetCode】226. Invert Binary Tree

时间:2015-07-12 15:24:50      阅读:230      评论:0      收藏:0      [点我收藏+]

Invert Binary Tree

Invert a binary tree.

     4
   /     2     7
 / \   / 1   3 6   9

to

     4
   /     7     2
 / \   / 9   6 3   1

Trivia:
This problem was inspired by this original tweet by Max Howell:

Google: 90% of our engineers use the software you wrote (Homebrew), but you can’t invert a binary tree on a whiteboard so fuck off.

 

递归。

/**
 * Definition for a binary tree node.
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
 * };
 */
class Solution {
public:
    TreeNode* invertTree(TreeNode* root) {
        if(root == NULL)
            return NULL;
        else
        {
            TreeNode* newleft = invertTree(root->right);
            TreeNode* newright = invertTree(root->left);
            root->left = newleft;
            root->right = newright;
            return root;
        }
    }
};

技术分享

【LeetCode】226. Invert Binary Tree

原文:http://www.cnblogs.com/ganganloveu/p/4640933.html

(0)
(0)
   
举报
评论 一句话评论(0
关于我们 - 联系我们 - 留言反馈 - 联系我们:wmxa8@hotmail.com
© 2014 bubuko.com 版权所有
打开技术之扣,分享程序人生!