在上篇ORACLE查看表空间对象中，我介绍了如何查询一个表空间有那些数据库对象，那么我们是否可以某个数据文件包含那些数据库对象呢？如下所示
SELECT E.SEGMENT_TYPE AS SEGMENT_TYPE
, E.SEGMENT_NAME AS SEGMENT_NAME , F.FILE_NAME AS FILE_NAME, SUM(E.BYTES)/1024/1024 AS SEGMENT_SIZE
FROM DBA_EXTENTS EINNER JOIN DBA_DATA_FILES F ON E.FILE_ID= F.FILE_ID
WHERE F.FILE_ID =109GROUP BY E.SEGMENT_TYPE,E.SEGMENT_NAME,F.FILE_NAME
ORDER BY 4 DESC;
SELECT E.SEGMENT_TYPE AS SEGMENT_TYPE
, E.SEGMENT_NAME AS SEGMENT_NAME , F.FILE_NAME AS FILE_NAME, SUM(E.BYTES)/1024/1024 AS SEGMENT_SIZE
FROM DBA_EXTENTS EINNER JOIN DBA_DATA_FILES F ON E.FILE_ID= F.FILE_ID
WHERE F.FILE_NAME =&FILE_NAMEGROUP BY E.SEGMENT_TYPE,E.SEGMENT_NAME,F.FILE_NAME
ORDER BY 4 DESC;
错误的写法，如下所示，DBA_SEGMENTS的HEADER_FILE表示ID of the file containing the segment header，主要是因为仅仅包含段对象的段头所在的文件。
SELECT ds.OWNER AS OWNER
,df.FILE_NAME AS FILE_NAME ,ds.SEGMENT_NAME AS SEGMENT_NAME ,ds.SEGMENT_TYPE AS SEGMENT_TYPE,SUM(ds.BYTES)/1024/1024 AS SEGMENT_SIZE
FROM DBA_SEGMENTS ds LEFT JOIN DBA_DATA_FILES df ON ds.HEADER_FILE = df.FILE_ID
WHERE ds.TABLESPACE_NAME=&TABLESPACE_NAME AND df.FILE_ID=&FILE_IDGROUP BY OWNER,FILE_NAME,SEGMENT_NAME,SEGMENT_TYPE
ORDER BY 4;
原文：http://www.cnblogs.com/kerrycode/p/4637107.html