Given a binary tree, find the maximum path sum.
The path may start and end at any node in the tree.
For example:
Given the below binary tree,
       1
      /      2   3
Return 6.
#include <iostream>
#include <vector>
#include <climits>
using std::vector;
/**
* Definition for a binary tree node.
* struct TreeNode {
*     int val;
*     TreeNode *left;
*     TreeNode *right;
*     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
struct TreeNode
{
    int val;
    TreeNode *left;
    TreeNode *right;
    TreeNode(int x) : val(x), left(NULL), right(NULL) {}
};
class Solution
{
private:
    int maxPathSum(TreeNode *root, int &Result)
    {
        if (!root)
        {
            return 0;
        }
        int RootResult = root->val;
        int LeftResult = maxPathSum(root->left, Result);
        int RightResult = maxPathSum(root->right, Result);
        LeftResult = LeftResult * (LeftResult > 0);
        RightResult = RightResult * (RightResult > 0);
        // all the tree
        int TmpResult = RootResult + LeftResult + RightResult;
        if (Result < TmpResult)
        {
            Result = TmpResult;
        }
        // only left subtree or the right subtree
        TmpResult = RootResult + (LeftResult > RightResult? LeftResult : RightResult);
        if (Result < TmpResult)
        {
            Result = TmpResult;
        }
        return TmpResult;
    }
public:
    int maxPathSum(TreeNode* root)
    {
        int Result = INT_MIN;
        maxPathSum(root, Result);
        return Result;
    }
};
版权声明:本文为博主原创文章,未经博主允许不得转载。
LeetCode_Binary Tree Maximum Path Sum
原文:http://blog.csdn.net/sheng_ai/article/details/46716081