Given a Weather table, write a SQL query to find all dates‘ Ids with higher temperature compared to its previous (yesterday‘s) dates.
+---------+------------+------------------+ | Id(INT) | Date(DATE) | Temperature(INT) | +---------+------------+------------------+ | 1 | 2015-01-01 | 10 | | 2 | 2015-01-02 | 25 | | 3 | 2015-01-03 | 20 | | 4 | 2015-01-04 | 30 | +---------+------------+------------------+For example, return the following Ids for the above Weather table:
+----+ | Id | +----+ | 2 | | 4 | +----+
select a.id from Weather a, Weather b where datediff(a.Date, b.Date) = 1 and a.Temperature > b.Temperature
Leetcode 197 Rising Temperature
原文：http://www.cnblogs.com/lilixu/p/4601571.html