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二级程序设计

时间:2014-03-23 12:53:17      阅读:551      评论:0      收藏:0      [点我收藏+]

/***a,b两数和c的竖式***/

#include<stdio.h>

int main(void)

{

         long a,b,c,p,q;

         printf("enter a and b:");

         scanf("%8ld%6ld",&a,&b);

         printf("%8ld\n",p=a);

         printf("%2c%6ld\n",‘+‘,q=b);

         printf(" %8s\n","--------");

         printf("%8ld\n",c=p+q);

         return 0;

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/***将小写字母换成大写字母(大小写字母的ASCII码相差32位,将小写字母的ASCII码减去32即得大写字母)***/

#include<stdio.h>

int main(void)

{

         char a,b;

 

         a=‘x‘;

         b=‘y‘;

         a-=32;

         b-=32;

         printf("%c %c\n%d %d\n",a,b,a,b);

         return 0;

}     

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#include<stdio.h>

int main(void)

{

         char a,b;

         a=‘X‘;

         b=‘Y‘;

         a+=32;

         b+=32;

         printf("%c %c\n%d %d\n",a,b,a,b);

         return 0;

}

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/****不借助第三变量,通过计算交换两个变量****/

#include<stdio.h>

int main(void)

{

               int a=10,b=20;

 

               printf("a=%d,b=%d\n",a,b);

               a+=b;

               b=a-b;

               a-=b;

               printf("a=%d,b=%d\n",a,b);

               return 0;

}

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/****一个数恰好等于它的因子之和,这个数就叫“完数”,找出1000以内的所有完数,并输出其因子****/

#include<stdio.h>

int main(void)

{

               int i,j,s;

               for(i=1;i<=1000;i++,s=1){

                   for(j=2;j<=i/2;j++)

                            if(i%j==0){

                                     s+=j;

                            }

                            if(s==i){

                                     printf("%d=1",i);

                                     for(j=2;j<=i/2;j++)

                                               if(i%j==0)

                                                        printf("+%d",j);

                                               printf("\n");

                            }

               }

               return 0;

}

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/***打印出所有符合其各位数字立方之和等于其本身的三位数***/

#include<stdio.h>

int main(void)

{

               int i,j,k,x;

               for(x=100;x<1000;x++){

                   i=x%10;

                   j=(x/10)/10;

                   k=x/100;

                   if(x==i*i*i+j*j*j+k*k*k)

                            printf("%d \n",x);

               }

               return 0;

}

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/****已知三位整数X和Y满足X+Y=1333,其中X的个位数是Y的百位数,Y的个位数是X的百位数,十位数一样,求满足条件的X和Y****/

#include<stdio.h>

int main(void)

{

               int i,j,k,x,y;

               for(i=1;i<=9;i++)

                   for(j=1;j<=9;j++)

                            for(k=1;k<=9;k++)

                                     if((i+k)*101+j*20==1333){

                                               x=i*100+j*10+k;

                                               y=k*100+j*10+i;

                                               printf("%d+%d=1333\n",x,y);

                                     }

                                     return 0;

}

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二级程序设计,布布扣,bubuko.com

二级程序设计

原文:http://www.cnblogs.com/zhaoruiqi/p/3618860.html

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