UVa10004 - Bicoloring

题目地址：点击打开链接

就是简单的BFS就可以了

C++代码：

#include <iostream>
#include <queue>
#include <cstring>
using namespace std;
const int maxsize = 210;
int n;
int graph[maxsize][maxsize];
int visieted[maxsize];
bool flag;
void bfs()
{
	visieted[0]=0;
	queue<int> qi;
	qi.push(0);
	while(!qi.empty())
	{
		int temp=qi.front();
		qi.pop();
		for(int i=0;i<n;++i)
		{
			if(i!=temp&&graph[temp][i]==1)
			{
				if(visieted[i]==-1)
				{
					visieted[i]=1-visieted[temp];
					qi.push(i);
				}
				else if(visieted[i]==visieted[temp])
				{
					flag = false;
					return;
				}
			}
		}
	}
}
int main()
{
	int l;
	while(cin>>n&&n)
	{
		cin>>l;
		int i;
		memset(graph,0,sizeof(graph));
		memset(visieted,-1,sizeof(visieted));
		int a,b;
		while(l--)
		{
			cin>>a>>b;
			graph[a][b]=graph[b][a]=1;
		}
		flag=true;
		bfs();
		if(flag)
			cout<<"BICOLORABLE."<<endl;
		else
			cout<<"NOT BICOLORABLE."<<endl;
	}
	return 0;
}

UVa10004 - Bicoloring,布布扣,bubuko.com

UVa10004 - Bicoloring

原文：http://blog.csdn.net/leizh007/article/details/21861679