首页 > 其他 > 详细

Rotate List

时间:2015-06-24 02:12:37      阅读:255      评论:0      收藏:0      [点我收藏+]

Given a list, rotate the list to the right by?k?places, where?k?is non-negative.

For example:
Given?1->2->3->4->5->NULL?and?k?=?2,
return?4->5->1->2->3->NULL.

?

/**
 * Definition for singly-linked list.
 * public class ListNode {
 *     int val;
 *     ListNode next;
 *     ListNode(int x) { val = x; }
 * }
 */
public class Solution {
    public ListNode rotateRight(ListNode head, int k) {
    	if (head == null) {
    		return null;
    	}
        Stack<ListNode> stack = new Stack<ListNode>();
        ListNode node = head;
        while (node != null) {
        	stack.push(node);
        	node = node.next;
        }
        k = k%stack.size();
        if (k == 0) {
        	return head;
        }
        ListNode tail = stack.peek();
        for (int i = k; i > 0; i--) {
        	node = stack.pop();
        }
        stack.peek().next = null;
        tail.next = head;
        return node;
    }
}

?

Rotate List

原文:http://hcx2013.iteye.com/blog/2221312

(0)
(0)
   
举报
评论 一句话评论(0
关于我们 - 联系我们 - 留言反馈 - 联系我们:wmxa8@hotmail.com
© 2014 bubuko.com 版权所有
打开技术之扣,分享程序人生!