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Rectangle Area

时间:2015-06-16 10:58:04      阅读:163      评论:0      收藏:0      [点我收藏+]

Rectangle Area

问题:

Find the total area covered by two rectilinear rectangles in a 2D plane.

Each rectangle is defined by its bottom left corner and top right corner as shown in the figure.

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Assume that the total area is never beyond the maximum possible value of int.
思路:

  数学的推导计算

我的代码:

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public class Solution {
    public int computeArea(int A, int B, int C, int D, int E, int F, int G, int H) {
        int oneArea = (C-A)*(D-B);
        int twoArea = (G-E)*(H-F);
        int left = Math.max(A, E);
        int right = Math.min(C, G);
        int down = Math.max(B, F);
        int top = Math.min(D, H);
        int intersect = 0;
        if(left < right && down < top)
            intersect = (right-left)*(top-down);
        return oneArea + twoArea - intersect;
    }
}
View Code

学习之处:

  • 是看了别人的代码才想到了怎么做,因为之前自己的代码太挫了,必须通过各种if else才能得到两个矩形的关系,别人的方法是通过左边界,右边界,上边界,下边界确定了矩形的面试,值得学习。

Rectangle Area

原文:http://www.cnblogs.com/sunshisonghit/p/4580069.html

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