Given a binary tree, return the inorder traversal of its nodes‘ values.
For example:
Given binary tree {1,#,2,3},
1
2
/
3
return [1,3,2].
Note: Recursive solution is trivial, could you do it iteratively?
def inorder_traversal(root) ans, stack = [], [[false,root]] while not stack.empty? visit, node = stack.pop if node stack << [false,node.right] << [true,node] << [false,node.left] if not visit ans << node.val if visit end end ans end
Leetcode 94 Binary Tree Inorder Traversal
原文：http://www.cnblogs.com/lilixu/p/4575083.html