Description:
Given a string s consists of upper/lower-case alphabets and empty space characters ‘ ‘, return the length of last word in the string.
If the last word does not exist, return 0.
Note: A word is defined as a character sequence consists of non-space characters only.
For example,
Given s = "Hello World",
return 5.
Code:
1 int lengthOfLastWord(string s) { 2 int temp = 0; 3 bool flag = false;//flag为真表示已经找到最后一个有效字符 4 for (int i = s.length()-1; i >= 0; --i) 5 { 6 if ( flag == false && s[i] != ‘ ‘) 7 { 8 flag = true; 9 temp = i; 10 continue; 11 } 12 if ( s[i] == ‘ ‘ && flag == true) 13 return temp - i; 14 } 15 16 if (flag == false)//全为空格 17 return 0; 18 return temp - i;//字符串中没有空格
原文：http://www.cnblogs.com/happygirl-zjj/p/4574669.html