Find the total area covered by two rectilinear rectangles in a 2D plane. 208MM

public class Solution {
	public static void main(String args[]){
		Solution a = new Solution();
		
		int c =a.computeArea(-2,-2,2,2,3,3,4,4);
		System.out.println(c);
	}
    public int computeArea(int A, int B, int C, int D, int E, int F, int G, int H) {
        int sqr = 0;
        sqr = (C-A>0? (C-A):(A-C) )* (D-B>0?(D-B):(B-D)) +(H>F? H-F:F-H)*(G>E?G-E:E-G);
        int result ;
        result = sqr - area(min(C,G),min(D,H),max(A,E),max(B,F));
        
        return(E>C||F>D||B>H||A>G)? sqr:result;
        
        
    }
    public int area(int A, int B, int C, int D){
    	int sqr;
    	sqr = (C-A>0? (C-A):(A-C) )* (D-B>0?(D-B):(B-D)) ;
    	return sqr;
    	
    }
    public int min(int a,int b){
    	int c;
    	c = a>b? b:a;
    	return c;
    }
    public int max(int a,int b){
    	int c;
    	c = a>b? a:b;
    	return c;
    }
}
//没考虑清楚，求面积不用判断符号，没有啥捷径目前发现
分析各种情况，总结条件，编写代码
有点像设计数字电路