2 2 1 10 3 2 5 4
Case #1: 0 Case #2: 1
#include <iostream>
#include<stdio.h>
#include<math.h>
#include<string.h>
#include<algorithm>
using namespace std;
#define N 100005
#define LL __int64
int a[N];
int b[N];
int fun(int n)
{
int i,t,cnt=0;
for(i=0;i<n;i++)
{
t=upper_bound(b,b+cnt,a[i])-b;
//printf("%d \n",t);
if(t==cnt)
cnt++;
b[t]=a[i];
}
return cnt;
}
int main()
{
int i,T,n,cnt=1;
scanf("%d",&T);
while(T--)
{
scanf("%d",&n);
for(i=0;i<n;i++)
{
scanf("%d",&a[i]);
a[i]-=i;
}
printf("Case #%d:%d\n",cnt++,n-fun(n));
}
return 0;
}
原文:http://blog.csdn.net/u011721440/article/details/46382867