Codeforces Round #305 (Div. 2), problem: (A) Mike and Fax

#include<iostream>
#include<cstdio>
#include<cstring>
using namespace std;

char a[1000+100];

bool judge(int m,int n)
{
    for(int i=m;i<=(m+n)/2;i++)
      if(a[i]!=a[m+n-i]) return 0;
    return 1;
}

int main()
{
    int k;
    while(~scanf("%s",a))
    {
        scanf("%d",&k);
        int len=strlen(a);
        if(len%k)  {  printf("NO\n"); continue; }

        int flag=0;
        int i;
        for(i=0;i<len;i+=len/k)
        if(judge(i,i+len/k-1)==0)   {  printf("NO\n"); flag=1; break; }

        if(!flag) printf("YES\n");
    }
    return 0;
}

Codeforces Round #305 (Div. 2), problem: (A) Mike and Fax

原文：http://blog.csdn.net/weirdomaybe/article/details/46128463