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LeetCode Rotate Array

时间:2015-05-24 21:58:25      阅读:147      评论:0      收藏:0      [点我收藏+]

Rotate an array of n elements to the right by k steps.

For example, with n = 7 and k = 3, the array [1,2,3,4,5,6,7] is rotated to [5,6,7,1,2,3,4].

Note:
Try to come up as many solutions as you can, there are at least 3 different ways to solve this problem.

[show hint]

Related problem: Reverse Words in a String II

Credits:
Special thanks to @Freezen for adding this problem and creating all test cases.

题意:左移k为数字。

思路:首先将数组分成两部分,先分别翻转后,再整个翻转。

public class Solution {
    public void rotate(int[] nums, int k) {
    	List<Integer> tmp1 = new ArrayList<Integer>();
    	List<Integer> tmp2 = new ArrayList<Integer>();
    	int n = nums.length;
    	k = k % n;
    	for (int i = 0; i < n-k; i++) 
    		tmp1.add(nums[i]);
    	for (int i = n-k; i < n; i++)
    		tmp2.add(nums[i]);
    	Collections.reverse(tmp1);
    	Collections.reverse(tmp2);
    	tmp1.addAll(tmp2);
    	Collections.reverse(tmp1);
    	for (int i = 0; i < n; i++)
    		nums[i] = tmp1.get(i);
    }
}



LeetCode Rotate Array

原文:http://blog.csdn.net/u011345136/article/details/45955013

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