LeeCode 删除数组中某一特定值的元素，并返回新的数组长度

题目：

Given an array and a value, remove all instances of that value in place and return the new length.

The order of elements can be changed. It doesn‘t matter what you leave beyond the new length.

int removeElement(int* nums, int numsSize, int val) {
    int count = 0;
    for(int i = 0; i<numsSize ; i++){
        if(nums[i] != val){
            nums[count++] = nums[i];
        }
    }
    return count;
}

LeeCode 删除数组中某一特定值的元素，并返回新的数组长度

原文：http://blog.csdn.net/xiaoshuoladashou/article/details/45849689