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LeetCode:Candy

时间:2015-05-19 16:35:04      阅读:218      评论:0      收藏:0      [点我收藏+]

题目描述:

There are N children standing in a line. Each child is assigned a rating value.

You are giving candies to these children subjected to the following requirements:

  • Each child must have at least one candy.
  • Children with a higher rating get more candies than their neighbors.

What is the minimum candies you must give?

思路分析:扫描两遍数组。第一遍从左到右,保证相邻的两个元素右边的值比左边的值大(如果右边的权重大于左边的)。第二部扫描从右到做,保证相邻的两个元素左边的值比右边的值大(如果左边的权重大于右边的)。


代码:

class Solution
{
	public:
		int candy(vector<int> & ratings)
		{
			int size = ratings.size();
			vector<int> number(size,1);
			for(int i = 1;i < size;i++)
			{
				if(ratings[i] > ratings[i-1])
					number[i] = number[i-1] + 1;
			}
			for(int i = size-1;i > 0;i--)
			{
				if(ratings[i-1] > ratings[i])
					number[i-1] = number[i] + 1 > number[i-1] ? number[i] + 1 : number[i-1];
			}
			int sum = 0;
			for(int i = 0;i < size;i++)
				sum = sum + number[i];
			return sum;
		}
};


LeetCode:Candy

原文:http://blog.csdn.net/yao_wust/article/details/45845237

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