Design a data structure that supports the following two operations:
void addWord(word) bool search(word)
search(word) can search a literal word or a regular expression string containing only letters
a-z or .. A . means it can represent any one letter.
For example:
addWord("bad")
addWord("dad")
addWord("mad")
search("pad") -> false
search("bad") -> true
search(".ad") -> true
search("b..") -> true
Note:
You may assume that all words are consist of lowercase letters a-z.
[思路]
1. 用一个set存. 超时.
2. 用trie来存.
[CODE]
public class WordDictionary {
Set<String> dict = new HashSet<String>();
// Adds a word into the data structure.
public void addWord(String word) {
dict.add(word);
}
// Returns if the word is in the data structure. A word could
// contain the dot character '.' to represent any one letter.
public boolean search(String word) {
if(dict.contains(word) ) return true;
else if(!word.contains(".")) return false;
for(int c='a'; c<='z'; c++) {
int i=0;
while(word.charAt(i++) != '.'){}
StringBuilder sb = new StringBuilder(word);
sb.setCharAt(i-1, (char)c);
if( search(sb.toString()) ) return true;
}
return false;
}
}
// Your WordDictionary object will be instantiated and called as such:
// WordDictionary wordDictionary = new WordDictionary();
// wordDictionary.addWord("word");
// wordDictionary.search("pattern");
leetcode : Add and Search Word - Data structure design
原文:http://blog.csdn.net/xudli/article/details/45840001