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Question Solution
Follow up for "Remove Duplicates":
What if duplicates are allowed at most twice?
For example,
Given sorted array nums = [1,1,1,2,2,3],
Your function should return length = 5, with the first five elements of nums being 1, 1, 2, 2 and 3. It doesn‘t matter what you leave beyond the new length.
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问题分析：去掉重复项，这里的重复是指3个以上，去重是指将3个以上项降为2个，还是使用传入的数组作为目标数组存储去重后结果，同时返回去重后的数组内数据个数
public class Solution {
public int removeDuplicates(int[] nums) {
int count=0;
int midc=0;
int size=nums.length;
if(size<=1)
return size;
int i;
for(i=0;i<nums.length-1;i++)
{
if(nums[i]!=nums[i+1])
{
midc++;
if(midc<2)
{
nums[count]=nums[i];
count=count+1;
}
else
{
nums[count]=nums[i];
nums[count+1]=nums[i];
count=count+2;
}
midc=0;
}
else
{
midc++;
}
}
if(midc==0)
{
nums[count]=nums[i];
count++;
}
else
{
nums[count]=nums[i];
nums[count+1]=nums[i];
count=count+2;
}
return count;
}
}
Leetcode#80Remove Duplicates from Sorted Array II
原文：http://7061299.blog.51cto.com/7051299/1651909