题意:就是……食物链嘛orz
解法:并查集+向量偏移。一!定!不!要!多!组!输!入!!!
代码:
难看死了
#include<stdio.h>
#include<iostream>
#include<algorithm>
#include<string>
#include<string.h>
#include<math.h>
#include<limits.h>
#include<time.h>
#include<stdlib.h>
#include<map>
#include<queue>
#include<set>
#include<stack>
#include<vector>
#define LL long long
using namespace std;
int father[50005], delta[50005];
void init()
{
for(int i = 0; i < 50005; i++)
father[i] = i;
memset(delta, 0, sizeof delta);
}
int Find(int a)
{
if(father[a] != a)
{
int tmp = Find(father[a]);
delta[a] = (delta[a] + delta[father[a]]) % 3;
father[a] = tmp;
}
return father[a];
}
int main()
{
int n, k;
scanf("%d%d", &n, &k);
init();
int ans = 0;
for(int i = 0; i < k; i++)
{
int a, b, c;
scanf("%d%d%d", &a, &b, &c);
if(b > n || c > n)
{
ans++;
continue;
}
int d, e;
d = Find(b), e = Find(c);
if(a == 1)
{
if(d == e)
{
//cout << "case1: " << delta[b] << " " << delta[c] << endl;
if(delta[b] != delta[c])
{
ans++;
//cout << "wrong: " << a << " " << b << " " << c << endl;
}
}
else
{
father[d] = e;
delta[d] = (delta[c] - delta[b] + 3) % 3;
}
}
else
{
if(d == e)
{
if(((delta[b] - delta[c] + 3) % 3) != 1)
{
ans++;
//cout << "wrong: " << a << " " << b << " " << c << endl;
}
}
else
{
father[d] = e;
delta[d] = (delta[c] - delta[b] + 4) % 3;
}
}
}
printf("%d\n", ans);
return 0;
}
原文:http://www.cnblogs.com/Apro/p/4504564.html