Time Limit: 3000/1000 MS (Java/Others) Memory Limit: 65535/32768 K (Java/Others)
Total Submission(s): 878 Accepted Submission(s): 308
水题啊。。直接统计额。。
#include<iostream>
#include<cstdio>
#include<cstdlib>
#include<cmath>
#include<cstring>
#include<string>
#include<algorithm>
using namespace std;
int n,m,mp[2001][2001],x,y,sum[2001][2001];
char s[2001][2001];
int main()
{
while(scanf("%d%d",&n,&m)!=EOF)
{
if(n==0&&m==0)
break;
scanf("%d%d",&x,&y);
memset(sum,0,sizeof(sum));
for(int i=1;i<=n;i++)
{
int cnt=0;
scanf("%s",s[i]+1);
for(int j=1;j<=m;j++)
{
if(s[i][j]==‘*‘)
cnt++;
sum[i][j]=sum[i-1][j]+cnt;
}
}
int ans=0;
for(int i=1;i<=n;i++)
{
for(int j=1;j<=m;j++)
{
if(i+x-1<=n&&j+y-1<=m)
{
int S=sum[i+x-1][j+y-1]-sum[i-1][j+y-1]-sum[i+x-1][j-1]+sum[i-1][j-1];
if(S==x*y)
ans++;
}
if(i+y-1<=n&&j+x-1<=m&&x!=y)
{
int S=sum[i+y-1][j+x-1]-sum[i-1][j+x-1]-sum[i+y-1][j-1]+sum[i-1][j-1];
if(S==x*y)
ans++;
}
}
}
printf("%d\n",ans);
}
return 0;
}
原文:http://www.cnblogs.com/water-full/p/4488672.html