如何将Swift中的多参函数转化成Curring函数

假设我们有一个含有多个参数的函数，用于构建一个人的基本信息：

func buildInfoWithName(name: String,#age: Int,#gender: String,#address: String,#phone: String) -> String {
    
    return "My name is " + name
        +  ",I'm a " + gender
        +  ",I live in " + address
        +  ",my phone number is " + phone
}

let mike = buildInfoWithName("Mike",age: 20,gender: "boy",address: "Tokyo Japan",phone: "12345678")

func buildInfoWithName(name: String)(age: Int)(gender: String)(address: String)(phone: String) -> String {
    
    return "My name is " + name
    +  ",I'm a " + gender
    +  ",I live in " + address
    +  ",my phone number is " + phone
}

let benson = buildInfoWithName("Benson")(age: 24)(gender: "boy")(address: "Chengdu Sichuan")(phone: "87654321")

参考链接： http://justtesting.org/post/94325843216/what-is-currying-in-swift

如何将Swift中的多参函数转化成Curring函数

原文：http://blog.csdn.net/tounaobun/article/details/45391523