首页 > 其他 > 详细

leetcode-26 Remove Duplicates from Sorted Array

时间:2015-04-29 17:09:02      阅读:149      评论:0      收藏:0      [点我收藏+]


问题描述:

Givena sorted array, remove the duplicates in place such that each element appearonly once and return the new length.

Do not allocate extra space for another array, youmust do this in place with constant memory.

For example,
Given input array A = 
[1,1,2],

Your function should return length = 2, and A isnow [1,2].

问题分析:使用一个count统计不同的元素个数,然后注意A[count] = A[i]来消除重复元素即可

代码:

public class Solution {
    public int removeDuplicates(int[] A) {
        if(A == null || A.length == 0)
			return 0;
		int count = 1;		
		for(int i = 1; i < A.length; i++)
		{
			if(A[i] != A[i - 1])
			{
				//更新A[count]
				A[count] = A[i];
			    //更新count
				count ++;
			}
		}
		return count;
    }
}

leetcode-26 Remove Duplicates from Sorted Array

原文:http://blog.csdn.net/woliuyunyicai/article/details/45368167

(0)
(0)
   
举报
评论 一句话评论(0
关于我们 - 联系我们 - 留言反馈 - 联系我们:wmxa8@hotmail.com
© 2014 bubuko.com 版权所有
打开技术之扣,分享程序人生!