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【leetcode】Swap Nodes in Pairs

时间:2015-04-24 11:57:42      阅读:279      评论:0      收藏:0      [点我收藏+]

Given a linked list, swap every two adjacent nodes and return its head.

For example,
Given 1->2->3->4, you should return the list as 2->1->4->3.

Your algorithm should use only constant space. You may not modify the values in the list, only nodes itself can be changed.

 

 1 /**
 2  * Definition for singly-linked list.
 3  * struct ListNode {
 4  *     int val;
 5  *     ListNode *next;
 6  *     ListNode(int x) : val(x), next(NULL) {}
 7  * };
 8  */
 9 class Solution {
10 public:
11     ListNode *swapPairs(ListNode *head) {
12        if (head == NULL)
13             return NULL;
14        if (head -> next == NULL)
15             return head;
16        ListNode *tmp = head -> next;
17        head -> next = swapPairs(tmp -> next);
18        tmp -> next = head;
19        return tmp;
20     }
21 };

 

【leetcode】Swap Nodes in Pairs

原文:http://www.cnblogs.com/jawiezhu/p/4452970.html

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