1. Two Sum

题目:

Given an array of integers, find two numbers such that they add up to a specific target number.

The function twoSum should return indices of the two numbers such that they add up to the target, where index1 must be less than index2. Please note that your returned answers (both index1 and index2) are not zero-based.

You may assume that each input would have exactly one solution.

Input: numbers={2, 7, 11, 15}, target=9
Output: index1=1, index2=2

题解：

使用HashMap，一次遍历数组，Time Complexity - O(n)，Space Complexity - O(n)

public class Solution {
    public int[] twoSum(int[] numbers, int target) {
        int result[] = {-1, -1};
        if(numbers == null || numbers.length == 0)
            return result;
        HashMap<Integer, Integer> map = new HashMap<Integer, Integer>();
        for(int i = 0; i < numbers.length; i++){
            if(!map.containsKey(target - numbers[i]))
                map.put(numbers[i], i);
            else{
                result[0] = map.get(target - numbers[i]) + 1;
                result[1] = i + 1;
                break;
           }    
        }
        return result;
    }
}

Reference:

http://www.cnblogs.com/springfor/p/3859618.html

1. Two Sum

原文：http://www.cnblogs.com/yrbbest/p/4427946.html