The Employee table holds all employees including their managers. Every employee has an Id, and there is also a column for the manager Id.
| Id | Name | Salary | ManagerId | 
|---|---|---|---|
| 1 | Joe | 70000 | 3 | 
| 2 | Henry | 80000 | 4 | 
| 3 | Sam | 60000 | NULL | 
| 4 | Max | 90000 | NULL | 
Given the Employee table, write a SQL query that finds out employees who earn more than their managers. For the above table, Joe is the only employee who earns more than his manager.
| Employee | 
|---|
| Joe | 
题目是要从Employee表中找到员工的工资大于自己manager工资的员工姓名。
实现方案也是MYSQL的内联,直接上AC SQL。
select e1.Name from Employee as e1 inner join Employee as e2 
on e1.ManagerId = e2.Id and e1.Salary > e2.Salary;[LeetCode]Employees Earning More Than Their Managers,解题报告
原文:http://blog.csdn.net/wzy_1988/article/details/45030839