接下来用java实现floyd算法:
private void Floyd() {
int i, j, k, n = pointSet.size();
for (i = 0; i < n; i++) {
for (j = 0; j < n; j++) {
D[i][j] = A[i][j];
if (i != j && A[i][j] < INFTY) {
path[i][j] = i;
} else {
path[i][j] = -1;
}
}
}
for (k = 0; k < n; k++) {
for (i = 0; i < n; i++) {
for (j = 0; j < n; j++) {
if (D[i][k] + D[k][j] < D[i][j]) {
D[i][j] = D[i][k] + D[k][j];
// 新的路径的前一点为k点到j点的路径的前一点。
path[i][j] = path[k][j];
}
}
}
}
}原文:http://blog.csdn.net/luo_xianming/article/details/44998227