<1>、通讯录访问
在iOS 6中，以前工作正常的访问通讯录的iPhone程序可能会出错，现象是程序启动时不提醒用户是否允许程序访问通讯录，同时在“设置->隐私->通讯录”中看不到你的程序。另外，对通讯录进行操作的代码会报类似于以下消息的错误：
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Could not compile statement for query (ABCCopyArrayOfAllInstancesOfClassInSourceMatchingProperties):
SELECT ROWID, Name, ExternalIdentifier, Type, ConstraintsPath, ExternalModificationTag, ExternalSyncTag, AccountID, Enabled, SyncData, MeIdentifier, Capabilities FROM ABStore WHERE Enabled = ?;
其原因是iOS 6加强了通讯录访问控制，要求开发人员显式声明需要访问通讯录，方法是调用 ABAddressBookRequestAccessWithCompletion
方法，具体参见官方文档：
http://developer.apple.com/library/ios/#releasenotes/General/RN-iOSSDK-6_0/index.html
下面是对应的样例代码，一般来讲需要将这段代码放置在程序启动部分，在程序启动过程中提示用户本程序需要访问设备上的通讯录：
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ABAddressBookRef addressBook = ABAddressBookCreate();
__block BOOL accessGranted = NO;
if (ABAddressBookRequestAccessWithCompletion != NULL) {
// we‘re on iOS 6
NSLog(@"on iOS 6 or later, trying to grant access permission");
dispatch_semaphore_t sema = dispatch_semaphore_create(0);
ABAddressBookRequestAccessWithCompletion(addressBook, ^(bool granted, CFErrorRef error) {
accessGranted = granted;
dispatch_semaphore_signal(sema);
});
dispatch_semaphore_wait(sema, DISPATCH_TIME_FOREVER);
dispatch_release(sema);
}
else { // we‘re on iOS 5 or older
NSLog(@"on iOS 5 or older, it is OK");
accessGranted = YES;
}
if (accessGranted) {
NSLog(@"we got the access right");
}
原文：http://www.cnblogs.com/whuishine/p/3451578.html