leetcode Reverse Integer

 1 int reverse(long long x)
 2 {
 3     long long m = x;
 4     if (x<INT_MIN||x > INT_MAX)
 5     {
 6         return 0;
 7     }
 8     if (m < 0)
 9     {
10         return 0 - reverse(0 - m);
11     }
12     long long y = 0;
13     while (m > 0)
14     {
15         int c = m % 10;
16         m = m / 10;
17         y = y * 10 + c;
18     }
19     if (y<INT_MIN || y>INT_MAX)
20     {
21         return 0;
22     }
23     return y;
24 }