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php对象编程的遇到的BUG!

时间:2015-03-26 16:32:50      阅读:288      评论:0      收藏:0      [点我收藏+]

自己写了个db链式操作模型对象如下代码所示(只摘取了其中一小段)遇到的bug

    public function insert(Array $c, $p = ‘INSERT‘) {
        if(!is_null($this->px)) return $this;
        function i( $c, $e = ‘,‘) {
            $d = ‘‘;
            foreach ($c as $val) {
                # code...
                $d .= $e . ‘(‘;
                foreach ($val as $valTow) {
                    $d .= ‘"‘ . $valTow . ‘",‘;
                    $d = trim($d, ‘,‘);
                }
                
                // var_dump($d);
                $d      .= ‘)‘; 
            }
            return rtrim($d, ‘)‘);
        }
        $n = ‘(‘;
        $d = ‘(‘;
        foreach ($c as $key => $value) {
            $n .= ‘`‘ . $key . ‘`,‘;
            if(is_array($value)) {
                $d = i($value);
            } else {
                $d .= ‘"‘ . $value . ‘",‘;
            }
        }
        $n      = rtrim($n, ‘,‘) . ‘)‘;
        $d      = rtrim($d, ‘,)‘);
        $d      .= ‘)‘;
        
        $this->insert = $p . ‘ INTO ‘ . $this->tableName . " {$n} VALUES {$d} ";
        $this->px = __METHOD__;
        return $this;
    }

仔细观看会发现方法里面定义了一个函数这里如果这个函数同时被调用则会爆出一个i函数不能被重复定义的错误!

解决办法很简单!就是将i函数写到其他地方或者写成对象方法;

所以建议不要在多次运行的方法里面这么定义函数!

如果对象只被调用一次则可以这么写!

做出如下修改就可以轻松解决问题了!(这只是其中一个解决方案!)

    public function insert(Array $c, $p = ‘INSERT‘) {
        if(!is_null($this->px)) return $this;
        
        $n = ‘(‘;
        $d = ‘(‘;
        foreach ($c as $key => $value) {
            $n .= ‘`‘ . $key . ‘`,‘;
            if(is_array($value)) {
                $d = $this->i($value);
            } else {
                $d .= ‘"‘ . $value . ‘",‘;
            }
        }
        $n      = rtrim($n, ‘,‘) . ‘)‘;
        $d      = rtrim($d, ‘,)‘);
        $d      .= ‘)‘;
        
        $this->insert = $p . ‘ INTO ‘ . $this->tableName . " {$n} VALUES {$d} ";
        $this->px = __METHOD__;
        return $this;
    }
    
    private function i( $c, $e = ‘,‘) {
            $d = ‘‘;
            foreach ($c as $val) {
                # code...
                $d .= $e . ‘(‘;
                foreach ($val as $valTow) {
                    $d .= ‘"‘ . $valTow . ‘",‘;
                    $d = trim($d, ‘,‘);
                }
                
                // var_dump($d);
                $d      .= ‘)‘; 
            }
            return rtrim($d, ‘)‘);
    }

 

php对象编程的遇到的BUG!

原文:http://www.cnblogs.com/dsphper/p/4368790.html

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