这题推推公式就可以了
先利用n1 = m2, n2 = m3,可以构造出所有边的比例关系
然后海伦公式 p = (a + b + c) / 2 S = sqrt(p * (p - a) * (p - b) * (p - c));
又有S = (a + b + c) / r / 2
两式子联立,就可以求出各边长度,然后就可以求出面积
代码:
#include <cstdio> #include <cstring> #include <cmath> #include <algorithm> using namespace std; int t; double r, m1, n1, m2, n2, m3, n3; int main() { scanf("%d", &t); while (t--) { scanf("%lf%lf%lf%lf%lf%lf%lf", &r, &m1, &n1, &m2, &n2, &m3, &n3); n2 = n2 / m2 * n1; m2 = n1; n3 = n3 / m3 * n2; m3 = n2; double a = m1 + n1, b = m2 + n2, c = m3 + n3; double p = (a + b + c) / 2; double tmp = sqrt(p * (p - a) * (p - b) * (p - c)); double x = r / tmp * (a + b + c) / 2; printf("%.4f\n", x * x * tmp); } return 0; }
原文:http://blog.csdn.net/accelerator_/article/details/44649635