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LeetCode Unique Paths

时间:2015-03-26 10:53:01      阅读:221      评论:0      收藏:0      [点我收藏+]

A robot is located at the top-left corner of a m x n grid (marked ‘Start‘ in the diagram below).

The robot can only move either down or right at any point in time. The robot is trying to reach the bottom-right corner of the grid (marked ‘Finish‘ in the diagram below).

How many possible unique paths are there?

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Above is a 3 x 7 grid. How many possible unique paths are there?

Note: m and n will be at most 100.

题意:一个机器人位于矩阵的左上角,它只能向右或向下走,问走到右下角的路径数。

思路:简单的dp

class Solution {
public:
    int uniquePaths(int m, int n) {
        vector<vector<int> > f(m, vector<int>(n));       

        for (int i = 0; i < n; i++)
            f[0][i] = 1;
        for (int i = 0; i < m; i++) 
            f[i][0] = 1;

        for (int i = 1; i < m; i++) 
            for (int j = 1; j < n; j++)
                f[i][j] = f[i-1][j] + f[i][j-1];

        return f[m-1][n-1];
    }
};



LeetCode Unique Paths

原文:http://blog.csdn.net/u011345136/article/details/44645887

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