python2.7.5中使用debug输出,可以采用如下方式:
import urllib2 httpHandler = urllib2.HTTPHandler(debuglevel=1) httpsHandler = urllib2.HTTPSHandler(debuglevel=1) opener = urllib2.build_opener(httpHandler, httpsHandler) urllib2.install_opener(opener) response = urllib2.urlopen('http://www.baidu.com')
python3 中统一使用的是urllib模块库,将python2中的urllib和urllib2进行了整合,试图按上述方式编写代码如下(python3.4.2 window7/cmd):
import urllib.request httpHandler = urllib.request.HTTPHandler(debuglevel=1) httpsHandler = urllib.request.HTTPSHandler(debuglevel=1) #opener = urllib.request.build_opener(httpHandler) urllib.request.install_opener(opener) response = urllib.request.urlopen('http://www.baidu.com') with open("url_response.txt", "w") as f: print (response.read(), file=f)
还有另外一种方式,使用http.client模块,代码如下:
import urllib.request import http.client http.client.HTTPConnection.debuglevel = 1 response = urllib.request.urlopen('http://www.baidu.com') with open("url_response.txt", "w") as f: print (response.read(), file=f)
至于如何使用urllib模块实现此功能,还有待了解。
若有了解的,望指点一二~~
原文:http://blog.csdn.net/haoxizh/article/details/44619497