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LeetCode - Refresh - Search in Rotated Sorted Array II

时间:2015-03-23 15:11:01      阅读:146      评论:0      收藏:0      [点我收藏+]

Just skip the duplicated ones.

 1 class Solution {
 2 public:
 3     bool search(int A[], int n, int target) {
 4         int start = 0, end = n-1, mid = 0;
 5         while (start <= end) {
 6             while (start <= end && A[start] == A[start+1]) start++;
 7             while (start <= end && A[end] == A[end-1]) end--;
 8             mid = (start + end)/2;
 9             if (A[mid] == target) return true;
10             if (A[mid] >= A[start]) {
11                 if (A[mid] < target) {
12                     start = mid + 1;
13                 } else if (A[start] <= target) {
14                     end = mid-1;
15                 } else start = mid+1;
16             } else {
17                 if (A[mid] > target) {
18                     end = mid-1;
19                 } else if (A[end] >= target) {
20                     start = mid+1;
21                 } else end = mid-1;
22             }
23         }
24         return false;
25     }
26 };

 

LeetCode - Refresh - Search in Rotated Sorted Array II

原文:http://www.cnblogs.com/shuashuashua/p/4359539.html

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