Length of Last Word

Given a string s consists of upper/lower-case alphabets and empty space characters ‘ ‘, return the length of last word in the string.

If the last word does not exist, return 0.

Note: A word is defined as a character sequence consists of non-space characters only.

For example,
Given s = "Hello World",
return 5.

先把字符串最后的空格去掉，然后统计从后往前第一个单词中字母的个数。

 1 int lengthOfLastWord(char *s) {
 2     if(s == NULL) return 0;
 3     int i = strlen(s)-1;
 4     int count = 0;
 5     while(s[i] == ‘ ‘) i--;
 6     while(s[i] != ‘ ‘ && i>=0){
 7         count++;
 8         i--;
 9     }
10     return count;
11 }

Length of Last Word

原文：http://www.cnblogs.com/zhhc/p/4353776.html