Time Limit:500MS
Memory Limit:32768KB
Description
?Hey, welcome to HDOJ(Hangzhou Dianzi University Online Judge).In this problem, your task is to calculate SUM(n) = 1 + 2 + 3 + ... + n.
Input
The input will consist of a series of integers n, one integer per line.
Output
?For each case, output SUM(n) in one line, followed by a blank line. You may assume the result will be in the range of 32-bit signed integer.
Sample Input
1
100
Sample Output
1
5050
以下是代码：
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#include <cstdio>using namespace std;int main(){ int n,sum; while(scanf("%d",&n)!=EOF){ sum=0; for(int i=1;i<=n;i++)sum+=i; printf("%d\n\n",sum); }} |
原文：http://www.cnblogs.com/gzdaijie/p/4298085.html