题意:给出n,m,人的编号为 0到n-1,再给出m个关系,问能不能够进行拓扑排序
#include<iostream>
#include<cstdio>
#include<cstring>
#include<algorithm>
using namespace std;
int indegree[1005],queue[1005],head[1005];
struct Edge
{
int to;
int next;
} edge[1005];
int main()
{
int n,m,i,j,k,iq,a,b;
while(scanf("%d %d",&n,&m)!=EOF&&n&&m)
{
memset(head,-1,sizeof(head));
memset(indegree,0,sizeof(indegree));
for(i=1;i<=m;i++)
{
scanf("%d %d",&a,&b);
edge[i].to=b;
edge[i].next=head[a];
head[a]=i;
indegree[b]++;
}
iq=0;
for(i=0;i<n;i++)
{
if(indegree[i]==0)
{
queue[iq++]=i;
}
}
for(i=0;i<iq;i++)
{
for(k=head[queue[i]];k!=-1;k=edge[k].next)
{
indegree[edge[k].to]--;
if(indegree[edge[k].to]==0)
{
queue[iq++]=edge[k].to;
}
}
}
if(iq==n) printf("YES\n");
else
printf("NO\n");
}
}
原文:http://www.cnblogs.com/wuyuewoniu/p/4278372.html