| Time Limit: 1000MS | Memory Limit: 30000K | |
| Total Submissions: 10622 | Accepted: 3877 | 
Description
Input
Output
Sample Input
3 2 1 2 2 3 2 3 1 2 1 2
Sample Output
0
Source
/*************************************************************************
    > File Name: poj1847.cpp
    > Author: ALex
    > Mail: zchao1995@gmail.com 
    > Created Time: 2015年02月05日 星期四 14时37分08秒
 ************************************************************************/
#include <map>
#include <set>
#include <queue>
#include <stack>
#include <vector>
#include <cmath>
#include <cstdio>
#include <cstdlib>
#include <cstring>
#include <iostream>
#include <algorithm>
using namespace std;
const double pi = acos(-1);
const int inf = 0x3f3f3f3f;
const double eps = 1e-15;
typedef long long LL;
typedef pair <int, int> PLL;
const int N = 110;
int dp[N][N];
int main ()
{
	int n, a, b;
	while (~scanf("%d%d%d", &n, &a, &b))
	{
		memset (dp, inf, sizeof(dp));
		int k, j;
		for (int i = 1; i <= n; ++i)
		{
			scanf("%d", &k);
			if (k == 0)
			{
				continue;
			}
			k--;
			scanf("%d", &j);
			dp[i][j] = 0;
			while (k--)
			{
				scanf("%d", &j);
				dp[i][j] = 1;
			}
		}
		for (int i = 1; i <= n; ++i)
		{
			dp[i][i] = 0;
		}
		for (int k = 1; k <= n; ++k)
		{
			for (int i = 1; i <= n; ++i)
			{
				for (int j = 1; j <= n; ++j)
				{
					dp[i][j] = min (dp[i][k] + dp[k][j], dp[i][j]);
				}
			}
		}
		if (dp[a][b] != inf)
		{
			printf("%d\n", dp[a][b]);
		}
		else
		{
			printf("-1\n");
		}
	}
	return 0;
}原文:http://blog.csdn.net/guard_mine/article/details/43527945