题目原型:
Given a binary tree containing digits from 0-9 only, each root-to-leaf path could represent a number.
An example is the root-to-leaf path 1->2->3 which represents the number 123.
Find the total sum of all root-to-leaf numbers.
For example,
1
/ 2 3
The root-to-leaf path 1->2 represents the number 12.
The root-to-leaf path 1->3 represents the number 13.
Return the sum = 12 + 13 = 25.
基本思路:
本题的意思就是把每条路径代表的值想加,关键就是求路径。
public List<Integer> list = new ArrayList<Integer>();
public int sumNumbers(TreeNode root)
{
if(root==null)
return 0;
int sum = 0;
search(root, "");
for(Integer in : list)
{
sum+=in;
}
return sum;
}
public void search(TreeNode root,String str)
{
if(root.left==null&&root.right==null)
{
str = str + root.val;
list.add(Integer.parseInt(str));
}
else
{
if(root.left!=null)
search(root.left, str+root.val);
if(root.right!=null)
search(root.right, str+root.val);
}
}
Sum Root to Leaf Numbers,布布扣,bubuko.com
原文:http://blog.csdn.net/cow__sky/article/details/20566053