首页 > 其他 > 详细

Leetcode:Best Time to Buy and Sell Stock

时间:2015-01-15 12:35:27      阅读:206      评论:0      收藏:0      [点我收藏+]

Say you have an array for which the ith element is the price of a given stock on day i.

If you were only permitted to complete at most one transaction (ie, buy one and sell one share of the stock), design an algorithm to find the maximum profit.

分析:贪心算法。记录前面出现的price的最小值,然后用max(maxProfit, prices[i] - min)更新最大收益。代码如下:

class Solution {
public:
    int maxProfit(vector<int> &prices) {
        int maxPro = 0;
        int minPri = INT_MAX;
        
        for(int i = 0; i < prices.size(); i++){
            if(prices[i] < minPri) minPri = prices[i];
            else maxPro = max(maxPro, prices[i]-minPri);
        }
        
        return maxPro;
    }
};

 

Leetcode:Best Time to Buy and Sell Stock

原文:http://www.cnblogs.com/Kai-Xing/p/4225852.html

(0)
(0)
   
举报
评论 一句话评论(0
关于我们 - 联系我们 - 留言反馈 - 联系我们:wmxa8@hotmail.com
© 2014 bubuko.com 版权所有
打开技术之扣,分享程序人生!