You are climbing a stair case. It takes n steps to reach to the top.
Each time you can either climb 1 or 2 steps. In how many distinct ways can you climb to the top?
递推公式T(n) = T(n-1) + T(n-2);
class Solution
{
public:
int climbStairs(int n)
{
int pre;
int last;
if(n==0)
return 0;
if(n == 1)
return 1;
pre=1;
last=1;
int res=0;
for(int i=2; i<=n; i++)
{
res = pre+last;
pre = last;
last = res;
}
return res;
}
};原文:http://blog.csdn.net/shaya118/article/details/42644609