Implement wildcard pattern matching with support for ‘?‘ and ‘*‘.
‘?‘ Matches any single character.
‘*‘ Matches any sequence of characters (including the empty sequence).
The matching should cover the entire input string (not partial).
The function prototype should be:
bool isMatch(const char *s, const char *p)
Some examples:
isMatch("aa","a") → false
isMatch("aa","aa") → true
isMatch("aaa","aa") → false
isMatch("aa", "*") → true
isMatch("aa", "a*") → true
isMatch("ab", "?*") → true
isMatch("aab", "c*a*b") → false
sIdx记录在s的位置,pIdx记录在p的位置,match记录在s中查询匹配的开始位置,starIdx记录了上一个*的具体位置,使用回溯的思想。
public class Solution {
public boolean isMatch(String s, String p) {
int sIdx = 0,pIdx = 0,starIdx = -1,match = 0;
while(sIdx<s.length()){
if(pIdx<p.length()&&p.charAt(pIdx)=='*'){
starIdx = pIdx;
match = sIdx;
pIdx++;
}else if(pIdx<p.length()&&(p.charAt(pIdx)=='?'||p.charAt(pIdx)==s.charAt(sIdx))){
sIdx++;
pIdx++;
}else if(starIdx != -1){
pIdx = starIdx+1;
sIdx = ++match;
}else{
return false;
}
}
while(pIdx<p.length()&&p.charAt(pIdx)=='*'){
pIdx++;
}
if(pIdx==p.length()) return true;
return false;
}
}
原文:http://blog.csdn.net/guorudi/article/details/42642953