Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists.
Solutions:
/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode(int x) : val(x), next(NULL) {}
* };
*/
class Solution
{
public:
ListNode *mergeTwoLists(ListNode *l1, ListNode *l2)
{
if(l1 == NULL)
return l2;
if(l2 == NULL)
return l1;
ListNode* head;
ListNode* temp;
if(l1->val < l2->val)
{
head = l1;
temp = l2;
}
else
{
head = l2;
temp = l1;
}
ListNode* temp1 = head->next;
ListNode* now = head;
while(temp1!=NULL && temp!=NULL)
{
if(temp1->val > temp->val)
{
now->next = temp;
now = now->next;
temp = temp->next;
}
else
{
now->next = temp1;
now = now->next;
temp1 = temp1->next;
}
}
if(temp1 == NULL)
now->next = temp;
if(temp == NULL)
now->next = temp1;
return head;
}
};LeetCode--Merge Two Sorted Lists
原文:http://blog.csdn.net/shaya118/article/details/42538201