LeetCode Reverse Integer

题意：将数字反转

思路：注意要判断溢出就是了

class Solution {
public:
    int reverse(int x) {
        long long ans = 0;
        while (x) {
            ans = ans * 10 + (x % 10);
            x /= 10;
        }
        
        if (ans > INT_MAX)
            ans = 0;
        if (ans < INT_MIN)
            ans = 0;
        return ans;
    }
};

LeetCode Reverse Integer

原文：http://blog.csdn.net/u011345136/article/details/42487337