Time Limit: 3000/1000 MS
(Java/Others) Memory Limit: 32768/32768 K
(Java/Others)
Total Submission(s): 23374 Accepted
Submission(s): 8239
代码:
#include<stdio.h> #include<string.h> const int inf=0x3f3f3f3f; const int tol=202; int path[tol],sta[tol][tol]; int lowc[tol]; void Dijkstra( int n, int beg) { int i,j,minc; int vis[tol]={0}; vis[beg]=1; for(i=0;i<n;i++) { lowc[i]=sta[beg][i]; path[i]=beg; } lowc[beg]=0; path[beg]=-1; /*<root>*/ int pre=beg; for(i=1;i<n;i++) { minc=inf; for(j=0;j<n;j++) { if(vis[j]==0&&lowc[pre]+sta[pre][j]<lowc[j]) { lowc[j]=sta[pre][j]+lowc[pre]; path[j]=pre; } } for(j=0;j<n;j++) { if(vis[j]==0&&lowc[j]<minc) { minc=lowc[j]; pre=j; } } vis[pre]=1; } } int main() { int n,m,a,b,c,i,j; while(scanf("%d%d",&n,&m)!=EOF) { for(i=0;i<=n;i++) { for(j=0;j<=n;j++) { sta[i][j]=inf; } } while(m--) { scanf("%d%d%d",&a,&b,&c); if(sta[a][b]>c) /*<防止重边>*/ sta[a][b]=sta[b][a]=c; } scanf("%d%d",&a,&b); Dijkstra(n,a); //n表示的最大的点 if(lowc[b]==inf) puts("-1"); else printf("%d\n",lowc[b]); } return 0; }
HDUOJ--1874 畅通工程续,布布扣,bubuko.com
原文:http://www.cnblogs.com/gongxijun/p/3576812.html