Given an index k, return the kth row of the Pascal‘s triangle.
For example, given k = 3,
Return [1,3,3,1].
Note:
Could you optimize your algorithm to use only O(k) extra space?
public class Solution {
public List<Integer> getRow(int rowIndex) {
List<Integer> list = new ArrayList<>();
for(int i=0;i<rowIndex+1;i++){
for(int j=i-1;j>0;j--){
int element = list.get(j)+list.get(j-1);
list.set(j, element);
}
list.add(1);
}
return list;
}
}
[LeetCode]Pascal's Triangle II
原文:http://blog.csdn.net/guorudi/article/details/41653793